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1.What is the inradius of triangle ABC if side BA=BC=29 and if side AC= 42.

 

2.What is the circumradius ABC if side BA=BC=29 and if side AC= 42.

 Jan 5, 2024
edited by rerebas  Jan 5, 2024
edited by rerebas  Jan 5, 2024
 #1
avatar+126665 
+1

Inradius   =   r =    Area / semi-perimeter

 

semiperimeter  =  (29 + 29 + 42)  /  2 =   50  = s

 

Area =  sqrt ( s (s -a) (s - b) (s -c)        where a,b,c  are the side lenghts

So

sqrt [ 50 (21)(21)(8) ] =   21 * 20  =  420

 

So

 

r  =  420 / 50  =   42 / 5  =  8.4

 

 

cool cool cool

 Jan 7, 2024
 #2
avatar+126665 
+1

circumradius   = R =     abc   / ( 4 area)              where a,b,c are the sides

 

abc =  (29)(29)(42)  = 35322

 

area (from other answer)  =  420

4 * area =  1680

 

R  =    35322  /  1680    =    21.025

 

 

cool cool cool

 Jan 7, 2024

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