Quadrilateral ABCD is inscribed in this circle.
What is the measure of ∠A ?
Enter your answer in the box.
___°
Quadrilateral ABCD is inscribed in a circle.
What is the measure of angle A?
Enter your answer in the box.
m∠A= __°
+37157 The second one (the arc degrees intercepted by an inscribed angle is equal to TWICE the angle)
The two angles cover the complete 360 degrees of the triangle in their arcs
soooo 360 = 2 ( 3x+1 + 2x+9 )
180 = 5x +10
170 = 5x x = 170/5 = 34 degrees
a = 2(34) + 9 = 77 degrees
+37157 First one
Inscribed angles are 1/2 of the arc that they cover
the 121 degree angle covers 121 x2 = 242 degreees of the circle......
the other angle covers 360 - 242 = 118 degrees
so the angle in question = 118/2 = 59 degrees
+37157 The second one (the arc degrees intercepted by an inscribed angle is equal to TWICE the angle)
The two angles cover the complete 360 degrees of the triangle in their arcs
soooo 360 = 2 ( 3x+1 + 2x+9 )
180 = 5x +10
170 = 5x x = 170/5 = 34 degrees
a = 2(34) + 9 = 77 degrees
