+0  
 
+4
177
3
avatar+125 

Hopefully CPhill or Melody sees this and helps me out.

I don't want/need the full solution to this problem, as I just need help figuring out the problem. 

Any hints would be fine.

 

Here's the problem: 

In triangle ABC,  angle bisectors  AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

 

Please help me out! Any help would be greatly appreciated smiley

 

 
 

 Dec 16, 2020
 #1
avatar+11269 
0

In triangle ABC,  angle bisectors  AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

 

Hello EinsteinBrain29!

To solve your question, I need the following information:

Point D is the intersection of the bisector AD with the side BC,

or

point D is the point of contact of the inner circle with side BC? Then ID would be the radius of the inner circle.

I ask for a information.

laugh  !

 Dec 17, 2020
edited by asinus  Dec 17, 2020
edited by asinus  Dec 17, 2020
edited by asinus  Dec 17, 2020
 #2
avatar+1170 
+4

In a triangle, ABC,  angle bisectors  AD, CF and BE meet at a point I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The following is what we know:

 

DI = 3           BD = 4          BI = 5

 

FI = EI = DI = 3

 

∠AEB ≅ ∠CEB = 90º            ∠IBD = tan-1(3 / 4)  

 

This problem can be easily solved by using this information. 

Have fun.smiley

 Dec 17, 2020
 #3
avatar+125 
+6

Oh thanks for the hints! I think I can try to take it on from here! I'll reply back in here when I bump into problems. 

EinsteinBrain29  Dec 17, 2020

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