Hopefully CPhill or Melody sees this and helps me out.

**I don't want/need the full solution to this problem, as I just need help figuring out the problem. **

**Any hints would be fine.**

Here's the problem:

In triangle ABC, angle bisectors AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

Please help me out! Any help would be greatly appreciated

EinsteinBrain29 Dec 16, 2020

#1**0 **

In triangle ABC, angle bisectors AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

**Hello EinsteinBrain29! **

To solve your question, I need the following information:

Point D is the intersection of the bisector AD with the side BC,

or

point D is the point of contact of the inner circle with side BC? Then ID would be the radius of the inner circle.

I ask for a information.

!

asinus Dec 17, 2020

#2**+4 **

In a triangle, ABC, angle bisectors AD, CF and BE meet at a point I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The following is what we know:

DI = 3 BD = 4 BI = 5

FI = EI = DI = 3

∠AEB ≅ ∠CEB = 90º ∠IBD = tan^{-1}(3 / 4)

This problem can be easily solved by using this information.

Have fun.

jugoslav Dec 17, 2020

#3**+6 **

Oh thanks for the hints! I think I can try to take it on from here! I'll reply back in here when I bump into problems.

EinsteinBrain29
Dec 17, 2020