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# Please help CPhill, Melody, Alan? Just want some hints!

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Hopefully CPhill or Melody sees this and helps me out.

I don't want/need the full solution to this problem, as I just need help figuring out the problem.

Any hints would be fine.

Here's the problem:

In triangle ABC,  angle bisectors  AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

Please help me out! Any help would be greatly appreciated

Dec 16, 2020

#1
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In triangle ABC,  angle bisectors  AD,CF and BE meet at I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

Hello EinsteinBrain29!

To solve your question, I need the following information:

Point D is the intersection of the bisector AD with the side BC,

or

point D is the point of contact of the inner circle with side BC? Then ID would be the radius of the inner circle.

I ask for a information.

!

Dec 17, 2020
edited by asinus  Dec 17, 2020
edited by asinus  Dec 17, 2020
edited by asinus  Dec 17, 2020
#2
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In a triangle, ABC,  angle bisectors  AD, CF and BE meet at a point I. If DI=3, BD=4, and BI=5, then compute the area of triangle ABC.

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The following is what we know:

DI = 3           BD = 4          BI = 5

FI = EI = DI = 3

∠AEB ≅ ∠CEB = 90º            ∠IBD = tan-1(3 / 4)

This problem can be easily solved by using this information.

Have fun.

Dec 17, 2020
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Oh thanks for the hints! I think I can try to take it on from here! I'll reply back in here when I bump into problems.

EinsteinBrain29  Dec 17, 2020