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If $3x+7 \equiv 2$ (mod $16$), then $2x+11$ is congruent (mod $16$) to what integer between $0$ and $15$, inclusive?

 

P.S Please add an explanation.

 Jun 17, 2021

Best Answer 

 #1
avatar+2266 
+1

3x + 7 = 2 (mod 16)

3x + 7 = 18 (mod 16)

3x = 11 (mod 16)

3x = 27 (mod 16)

x = 9 (mod 16)

 

2*9 + 11 = 27 = 11 (mod 16)

 

=^._.^=

 Jun 17, 2021
 #1
avatar+2266 
+1
Best Answer

3x + 7 = 2 (mod 16)

3x + 7 = 18 (mod 16)

3x = 11 (mod 16)

3x = 27 (mod 16)

x = 9 (mod 16)

 

2*9 + 11 = 27 = 11 (mod 16)

 

=^._.^=

catmg Jun 17, 2021

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