If $3x+7 \equiv 2$ (mod $16$), then $2x+11$ is congruent (mod $16$) to what integer between $0$ and $15$, inclusive?
P.S Please add an explanation.
3x + 7 = 2 (mod 16)
3x + 7 = 18 (mod 16)
3x = 11 (mod 16)
3x = 27 (mod 16)
x = 9 (mod 16)
2*9 + 11 = 27 = 11 (mod 16)
=^._.^=
