+0

0
209
6

i don't have another equation, this is not a textbook question, but something i am trying to figure out myself ...

can we tell anything maybe about the relationship of x:y ?

thanks very much for your help !!

thanks again you guys for your help, i am now able to continue working on my project !! :)

Guest Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017
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#1
0

You have two variables and only one equation. You need two separate equations to find two separate variables. Have you put the whole question on the page?

Guest Jun 11, 2017
#2
0

hmmm, no i don't have another equation, this is not a textbook question, but something i am trying to figure out myself ... can we not tell anything maybe about the relationship of x:y ?  thanks very much for your help !!

Guest Jun 11, 2017
#3
0

You can re-arrange the expression to express y in terms of x and you will get the equation of a straight line.

y = 1/(2.307) -1  + x/(2.307)                       which is of the form  y= mx +c    when you tidy it up   --- which I leave to you.  I guess you know that  m is the gradient of the line  and c is the  y-value of the line's intercept with the  y - axis.

Guest Jun 11, 2017
#4
0

There is no unique solution to your equation. x and y can take any value. for example: If x=5, then y=1.6

or when y=5 then x=12.842........and so on for infinite number of solutions.

Guest Jun 11, 2017
#5
0

thanks again you guys for your help, i am now able to continue working on my project !! :)

Guest Jun 11, 2017
#6
+6928
0

\(\dfrac{1+x}{1+y}=2.307\\ 1 + x = 2.307+2.307y\\ 2.307y = x-1.307\\ y = \dfrac{x-1.307}{2.307}\)

Any (x, y) which satisfies this equation works. No particular x : y relation.

MaxWong  Jun 12, 2017

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