+0

0
422
6

i don't have another equation, this is not a textbook question, but something i am trying to figure out myself ...

can we tell anything maybe about the relationship of x:y ?

thanks very much for your help !!

thanks again you guys for your help, i am now able to continue working on my project !! :)

Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017
edited by Guest  Jun 11, 2017

#1
0

You have two variables and only one equation. You need two separate equations to find two separate variables. Have you put the whole question on the page?

Jun 11, 2017
#2
0

hmmm, no i don't have another equation, this is not a textbook question, but something i am trying to figure out myself ... can we not tell anything maybe about the relationship of x:y ?  thanks very much for your help !!

Jun 11, 2017
#3
0

You can re-arrange the expression to express y in terms of x and you will get the equation of a straight line.

y = 1/(2.307) -1  + x/(2.307)                       which is of the form  y= mx +c    when you tidy it up   --- which I leave to you.  I guess you know that  m is the gradient of the line  and c is the  y-value of the line's intercept with the  y - axis.

Jun 11, 2017
#4
0

There is no unique solution to your equation. x and y can take any value. for example: If x=5, then y=1.6

or when y=5 then x=12.842........and so on for infinite number of solutions.

Jun 11, 2017
#5
0

thanks again you guys for your help, i am now able to continue working on my project !! :)

Jun 11, 2017
#6
+7076
0

\(\dfrac{1+x}{1+y}=2.307\\ 1 + x = 2.307+2.307y\\ 2.307y = x-1.307\\ y = \dfrac{x-1.307}{2.307}\)

Any (x, y) which satisfies this equation works. No particular x : y relation.

Jun 12, 2017