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Please help! I am so confused. Please show work. Thank you!!

mathelp  Mar 28, 2018
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2+0 Answers

 #1
avatar+85673 
+3

n√a) m   can be written as    am/n  .....so.....

 

5(√a5 )  =    a5/5  =  (a1/5)5  = a  ⇒   Answer  C

 

 

 

Second one

3√ [216a3b9 ]  =  3√216  * 3√a3  *  3√b9    =  (63)1/3 * (a3)1/3 * (b9)1/3  = 

 

6ab⇒ Answer C

 

 

Last one....look at answer B

 

√[98 j9c8]  = √{49*2]  * √ [j9 ] * √[c8 ]   =

 

√49  * √2  * √ [j8]  * √j  * √[c8 ]   =

 

7  * √2  *  (j8)1/2  * √j  *  (c8)1/2    =

 

7j4c4√[ 2j ]   

 

 

 

cool cool cool   

CPhill  Mar 28, 2018
 #2
avatar+6943 
+3

\(7j^4c^4\sqrt{2j}\)

 

Square and square root the expression.

 

\(=\,\sqrt{\bigg(7j^4c^4\sqrt{2j}\bigg)^2}\\~\\ =\,\sqrt{7^2(j^4)^2(c^4)^2(\sqrt{2j})^2\vphantom{\bigg)}}\\~\\ =\,\sqrt{49j^8c^8(2j)\vphantom{\bigg)} }\\~\\ =\,\sqrt{49\cdot2\cdot j^8\cdot j\cdot c^8\vphantom{\bigg)} }\\~\\ =\,\sqrt{98j^9c^8 \vphantom{\big)}}\)

hectictar  Mar 28, 2018

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