Find the equation of the line in slope intercept form that is perpendicular to 2x+3y-12=0 and passes through the point (-3, -5). show your work

Guest Jul 25, 2020

#1**+1 **

Find the slope, m , of the given line.....do you know how to do that?

PERPINDICULAR slope will be - 1/m

then use the line form y = -1/m x + b sub in the x,y point given to calulate 'b'

ElectricPavlov Jul 25, 2020

#2**0 **

The equation of the circle is x2+y2=4x2+y2=4. Thus, the centre of the circle is (0,0)(0,0) and radius is 2.

Since the line y=x+n⇒x−y+n=0y=x+n⇒x−y+n=0 is a tangent, the perpendicular distance from the point (0,0) to the tangent will be 2.

Thus, we get:

∣∣x−y+n2√∣∣=2|x−y+n2|=2

⇒∣∣0−0+n2√∣∣=2⇒|0−0+n2|=2

⇒n=±22–√⇒n=±22

Thus the two tangent equations are y=x±22–√y=x±22.

Guest Jul 25, 2020