Find the equation of the line in slope intercept form that is perpendicular to 2x+3y-12=0 and passes through the point (-3, -5). show your work
+37146 Find the slope, m , of the given line.....do you know how to do that?
PERPINDICULAR slope will be - 1/m
then use the line form y = -1/m x + b sub in the x,y point given to calulate 'b'
The equation of the circle is x2+y2=4x2+y2=4. Thus, the centre of the circle is (0,0)(0,0) and radius is 2.
Since the line y=x+n⇒x−y+n=0y=x+n⇒x−y+n=0 is a tangent, the perpendicular distance from the point (0,0) to the tangent will be 2.
Thus, we get:
∣∣x−y+n2√∣∣=2|x−y+n2|=2
⇒∣∣0−0+n2√∣∣=2⇒|0−0+n2|=2
⇒n=±22–√⇒n=±22
Thus the two tangent equations are y=x±22–√y=x±22.
