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If the inverses of two functions are both functions, will the inverse of the product or quotient of the original functions also be a function? Example too please..

 Sep 21, 2016
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Not all products (or quotients) of the invertible functions will have inverses

 

Examples:

 

f(x) = 1/x

f(x)  = 1/x^2

 

Both of these have inverses

 

Product of the original functions =  1/x^3    this is one-to-one  so it has an inverse function

Quotient of the original functions  = either  x  or 1/x.......both of these are one-to-one  so both have inverse functions

 

However consider :

 

f(x)  = x - 3

f(x) = x + 5

 

Both of these functions are one-to-one and thus have inverses

 

However........their product =  x^2 + 2x - 15......and this is not a one-to-one function, so it will have no inverse [ unless we restrict the domain]

 

 

 

cool cool cool

 Sep 21, 2016

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