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Please Help

 

 Apr 1, 2020
edited by Mathisgood  Apr 1, 2020
edited by Mathisgood  Apr 1, 2020
 #1
avatar+336 
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Never mind. The picture used to say  "Wait for moderation." ???

 Apr 1, 2020
edited by nchang  Apr 1, 2020
 #2
avatar+210 
+1

If you solved it yourself, good for you!

Actually, could you tell me how you got your answer? I'm curious.

 Apr 1, 2020
 #3
avatar+336 
+1

I think I might know. He first found the area of the whole circle and multiplied it by 150/360 (to find the area of the sector) and then subtracted the area of the triangle.

 Apr 1, 2020
 #4
avatar+336 
+1

How might you find the area of the triangle? :)

 Apr 1, 2020
 #5
avatar+210 
+1

The triangle part has got me stumped, but then, I haven't really given it a lot of thought.

Impasta  Apr 1, 2020
 #6
avatar+20876 
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You can find the area of the triangle by using the formula:  Area  =  ½·a·b·sin(C)

 Apr 1, 2020
 #7
avatar+210 
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I was hoping there was some non-trig way. Most of the math I do doesn't involve trig, and so I'm not very good at it.

Impasta  Apr 1, 2020
 #8
avatar+692 
+1

 

r = 27.8

 

Area of sector   As = [(r²pi) /360°] * 150° = 1011.645194 in²

 

Area of triangle   At = [ sin(15°) * 27.8] * [ cos(15°) * 27.8 ] = 193.21 in²

 

Shaded area       A = As - At = 818.435194 in²   indecision

 Apr 1, 2020
edited by Dragan  Apr 1, 2020

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