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Solve $\frac{1}{3} t - 5 < t - 2 \le -3t + 7.$ Give your answer as an interval.

 Mar 26, 2021
 #1
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-1

The solution is (6/5, 13/4].

 Mar 26, 2021
 #2
avatar+96 
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That is not correct. Thank you though.

Immaguest  Mar 26, 2021
 #3
avatar+96 
0

The answer is 144.

 Mar 26, 2021
 #4
avatar+128079 
+1

We have two  inequalities  to solve

 

(1/3)t  - 5 <  t  - 2                   and                 t  - 2 ≤ -3t + 7

 

add 2 to both sides,                                       add 2, 3t to both sides                                 

subtract 1/3t from both sides                         

 

-3 < t - (1/3)t                                                   4t ≤  9

 

-3  < (2/3)t                                                         t ≤  9/4

 

(-3)(3/2) < t

 

-9/2 < t

 

So  t  =   ( -9/2 , 9/4 ] 

 

 

cool cool cool

 Mar 26, 2021

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