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Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

 

Ive seen the other answers on this site, but none of them make any sense... i just need the answers. Idc about the explaination. 

 

Thanks!

 Mar 5, 2021
 #1
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sqrt(4x^2) - sqrt(x^2) = 6

2x - x = 6

x = $\boxed{6}$

 Mar 5, 2021
 #2
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Thats not right

 #3
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You're going to get the explanation anyway. 

You're not the only one who reads these threads. 

 

Take into account that square roots are both positive and negative.

 

sqrt(4x2)  =  +2x and –2x   (i.e., plus and minus roots)  

sqrt (x2)   =  +x   and –x  

 

   2x – x = 6        gives you x = 6  

 

 –2x – x = 6        gives you x = –2  

 

  2x – (–x) = 6     gives you x = 2  

 

–2x – (–x) = 6     gives you x = –6  

 Mar 5, 2021
edited by Guest  Mar 5, 2021
 #4
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GeEz OkAy

 

Thats right. Thx so much 

 #6
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Why are you answering when Ayden is a very obvious cheat?

 

Answering obvious cheats just gives this forum a really bad reputation.

Melody  Mar 7, 2021

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