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Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

Ive seen the other answers on this site, but none of them make any sense... i just need the answers. Idc about the explaination.

Thanks!

Mar 5, 2021

#1
-1

sqrt(4x^2) - sqrt(x^2) = 6

2x - x = 6

x = $\boxed{6}$

Mar 5, 2021
#2
+8
-2

Thats not right

#3
-1

You're going to get the explanation anyway.

You're not the only one who reads these threads.

Take into account that square roots are both positive and negative.

sqrt(4x2)  =  +2x and –2x   (i.e., plus and minus roots)

sqrt (x2)   =  +x   and –x

2x – x = 6        gives you x = 6

–2x – x = 6        gives you x = –2

2x – (–x) = 6     gives you x = 2

–2x – (–x) = 6     gives you x = –6

Mar 5, 2021
edited by Guest  Mar 5, 2021
#4
+8
-2

GeEz OkAy

Thats right. Thx so much

#6
+114476
0

Why are you answering when Ayden is a very obvious cheat?

Answering obvious cheats just gives this forum a really bad reputation.

Melody  Mar 7, 2021