Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

Ive seen the other answers on this site, but none of them make any sense... i just need the answers. Idc about the explaination.

Thanks!

AydenFilmoreismybro Mar 5, 2021

#3**-1 **

You're going to get the explanation anyway.

You're not the only one who reads these threads.

Take into account that square roots are both positive and negative.

sqrt(4x^{2}) = +2x __and__ –2x (i.e., plus and minus roots)

sqrt (x^{2}) = +x and –x

2x – x = 6 gives you x = 6

–2x – x = 6 gives you x = –2

2x – (–x) = 6 gives you x = 2

–2x – (–x) = 6 gives you x = –6

Guest Mar 5, 2021

edited by
Guest
Mar 5, 2021