A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue ?Write your answer as a fraction in simplest form.

Guest May 3, 2019

#1**-1 **

To solve this problem, do this...

Multiply the probabilities of the outcomes. 4/10*6/10 = 24/100 = 12/50 = 6/25.

**The answer is 6/25.**

~~Hypotenuisance

Hypotenuisance May 3, 2019

#1**-1 **

Best Answer

To solve this problem, do this...

Multiply the probabilities of the outcomes. 4/10*6/10 = 24/100 = 12/50 = 6/25.

**The answer is 6/25.**

~~Hypotenuisance

Hypotenuisance May 3, 2019

#4**0 **

What you can learn from this is that whenever it asks you the probability of something happening then the probability something else happening, you can find the total probability by multiplying both probabilities.

So if a spinner has 10 sections and 2 are blue and 8 are orange.

You will do 2/10 * 8/10 = 16/100 -> 4/25.

CalculatorUser
May 4, 2019