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Determine if the graph of the equation below is a parabola, circle, ellipse, hyperbola, point, line, two lines, or empty. Enter the most specific answer.

\((x-3)^2 + y^2 = 10\)

 

Thank you for helping! smiley

 Feb 2, 2021
 #1
avatar+113118 
+1

you should be able to work this out very easily for yourself.

 

Try putting it into here and see what happens

 

https://www.desmos.com/calculator

 Feb 2, 2021
 #2
avatar+118505 
+1

(x - 3)^2  + y^2  =  10

 

x^2 - 6x  + 9  + y^2  =  10

 

1x^2   + 1 y^2  - 6x   - 1   =   0

 

When  we have the form

 

Ax^2  + By^2  +  Cx   + Dy  +  E    =   0

 

If A  = B      (and E  is negative)     then we  have a circle

 

 

cool cool cool

 Feb 2, 2021
 #4
avatar+79 
0

Thank you!

StarsIsTheLimit  Feb 3, 2021
 #3
avatar+113118 
+1

It was already in the most obvious form Chris.

 

\((x-3)^2+y^2 =\sqrt{10}^2\\ centre(3,0)\;\;radius \sqrt{10}\)

 

If the kid looked at his formula notes.

Or if he went to desmos and graphed it, he would have known that.

 

I give partial answers for good reasons.

 Feb 2, 2021
 #5
avatar+79 
+1

I will try to work it out by myself next time.

StarsIsTheLimit  Feb 3, 2021
 #6
avatar+113118 
0

Good, it pleases me to hear that. 

Melody  Feb 3, 2021

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