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Determine if the graph of the equation below is a parabola, circle, ellipse, hyperbola, point, line, two lines, or empty. Enter the most specific answer.

$$(x-3)^2 + y^2 = 10$$

Thank you for helping! Feb 2, 2021

#1
+1

you should be able to work this out very easily for yourself.

Try putting it into here and see what happens

https://www.desmos.com/calculator

Feb 2, 2021
#2
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(x - 3)^2  + y^2  =  10

x^2 - 6x  + 9  + y^2  =  10

1x^2   + 1 y^2  - 6x   - 1   =   0

When  we have the form

Ax^2  + By^2  +  Cx   + Dy  +  E    =   0

If A  = B      (and E  is negative)     then we  have a circle   Feb 2, 2021
#4
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Thank you!

StarsIsTheLimit  Feb 3, 2021
#3
+1

It was already in the most obvious form Chris.

$$(x-3)^2+y^2 =\sqrt{10}^2\\ centre(3,0)\;\;radius \sqrt{10}$$

If the kid looked at his formula notes.

Or if he went to desmos and graphed it, he would have known that.

I give partial answers for good reasons.

Feb 2, 2021
#5
+1

I will try to work it out by myself next time.

StarsIsTheLimit  Feb 3, 2021
#6
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Good, it pleases me to hear that.

Melody  Feb 3, 2021