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A fruit seller had the same number of papayas and mangoes at first. He

threw away 85 rotten papayas and sold 1/4 of his remaining papayas. He

threw away 60 rotten mangoes and sold 1/3 of his remaining mangoes. After

that, he was left with an equal number of papayas and mangoes.

(a)  How many papayas did the fruit seller have at first?

(b)  The fruit seller sold his mangoes at 3 for $5.80. How much did he collect from the sale of the mangoes? Nov 9, 2021 ### 1+0 Answers #1 +1 No. of papayas = No. of mangoes = x He threw 85 papayas then remaining papayas = x - 85 sold = (x-85) * 1/4 -----(1) He threw 60 rotten mangoes the remaining mangoes = (x - 60) sold mangoes = (x - 60) 1/3. Now (No. of Remaining) ( Mangoes after ) = (No. of Remaining) ( selling ) ( papayas after ) ( selling ) (x - 85) - ($${x - 85\over 4}$$) = (x - 60) - ($${x - 60 \over 3})$$ => (x - 85) (1 - $${1 \over 4}$$) = (x - 60) (1 - $${1 \over 3}$$) => (x - 85) * 3/4 = (x - 60) 2/3 => 9x - 85 * 9 = 8x - 60 * 8 => x = 85 * 9 - 60 * 8 = 765 - 480 x = 285 sold mangoes (x - 60) * $${1 \over 3}$$ = ($${(285 - 60) \over 3} = {225 \over 3} =$$ = 75 3 For$ 5.8

Collected Money = $${75 \over 3} * 5.8$$

= 25 * 5.8 = 145.0\$

Ans

Nov 14, 2021