A fruit seller had the same number of papayas and mangoes at first. He
threw away 85 rotten papayas and sold 1/4 of his remaining papayas. He
threw away 60 rotten mangoes and sold 1/3 of his remaining mangoes. After
that, he was left with an equal number of papayas and mangoes.
(a) How many papayas did the fruit seller have at first?
(b) The fruit seller sold his mangoes at 3 for $5.80. How much did he
collect from the sale of the mangoes?
No. of papayas = No. of mangoes = x
He threw 85 papayas
then remaining papayas = x - 85
sold = (x-85) * 1/4 -----(1)
He threw 60 rotten mangoes the
remaining mangoes = (x - 60)
sold mangoes = (x - 60) 1/3.
Now (No. of Remaining)
( Mangoes after ) = (No. of Remaining)
( selling ) ( papayas after )
( selling )
(x - 85) - (\( {x - 85\over 4}\)) = (x - 60) - (\( {x - 60 \over 3})\)
=> (x - 85) (1 - \({1 \over 4}\)) = (x - 60) (1 - \( {1 \over 3}\))
=> (x - 85) * 3/4 = (x - 60) 2/3
=> 9x - 85 * 9 = 8x - 60 * 8
=> x = 85 * 9 - 60 * 8
= 765 - 480
x = 285
sold mangoes (x - 60) * \( {1 \over 3}\)
= (\( {(285 - 60) \over 3} = {225 \over 3} = \)
= 75
3 For $ 5.8
Collected Money = \( {75 \over 3} * 5.8\)
= 25 * 5.8 = 145.0$
Ans
