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please help me on my AOPS alcumus

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A number in the set {50, 51, 52, 53...,999} is randomly selected . What is the probability that it is a two-digit number? Express your answer as a common fraction.

 Jun 15, 2020

3+0 Answers

 #1
avatar+1005 
+1

There are 50-99 of two digit numbers

 

THus, 1 - 50

 

50 numbers.

 

50-999 becomes 1 - 950

 

So we have 50/950 = 5/95 = 1/19

 

Is this correct?

 Jun 15, 2020
 #2
avatar+333 
+8

thanks (it is correct)

 Jun 15, 2020
 #3
avatar+1262 
+4

1/19 since there are 1000-50=950 numbers and there are 100-50=50 2 digit numbers so 50/950=1/19

 Jun 15, 2020

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