A group of pirates captures Kevin, Lisa, Matt, and Neal, and forces them to play a game. They each roll a fair 6-sided-die once. If the product of their roll is a multiple of 3, they all have to walk the plank, but otherwise, they are safe. What is the probability that they survive?
(An explanation + answer would be amazing, but it's fine if you can only answer!)
(Literally anyone I need help FAST)
There are 1040 (that begin with 1113 and end with 6666) multiples of 3 in rollings of 4 dice. Therefore, there are:6^4 - 1040 =256 combinations that are NOT multiples of 3. So, 256 / 6^4 =256 / 1296 =16 / 81 =19.75% -Their chance of survival.