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A group of pirates captures Kevin, Lisa, Matt, and Neal, and forces them to play a game. They each roll a fair 6-sided-die once. If the product of their roll is a multiple of 3, they all have to walk the plank, but otherwise, they are safe. What is the probability that they survive?

 

A)2/3  

B)16/81  

C)145/1296

D)65/81

E)625/1296

 

(An explanation + answer would be amazing, but it's fine if you can only answer!)

(Literally anyone I need help FAST)

 Aug 13, 2020
edited by Guest  Aug 13, 2020
 #1
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There are 1040 (that begin with 1113 and end with 6666) multiples of 3 in rollings of 4 dice. Therefore, there are:6^4  -  1040 =256 combinations that are NOT multiples of 3. So, 256 / 6^4 =256 / 1296 =16 / 81 =19.75% -Their chance of survival.

 Aug 13, 2020
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Speaking as the person who asked the question, is it possible for the chance of survival to be lower than the chance of walking the plank when the ratio would be 2/3:1/3?

NerdyWeeb  Aug 14, 2020

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