+0

+2
483
9
+152

$$a=\frac{v}{t}$$                            solve for t

$$A=\pi r^2$$                        solve for r

$$P=I^2R$$                       solve for I

xRainexSiderisx  Mar 21, 2017
#1
+12735
+3

a = v/t     Multiply both sides of the equation by 't

at = v      Divide both sides by 'a'

t = v/a

A=pi r^2     Divide both sides by pi

A/pi = r^2    Sqrt both sides

sqrt(A/pi) = r                                 Do you see how it is done?   Can you do the third one?

ElectricPavlov  Mar 21, 2017
#3
+7266
+2

Hey you beat me to it...the feature that shows other users who are composing doesn't seem to be working anymore

hectictar  Mar 21, 2017
edited by hectictar  Mar 21, 2017
#4
+152
+2

Yes I can! Thanks!

xRainexSiderisx  Mar 21, 2017
#6
+12735
+2

I think you are correct....can honestly say I have not found ONE SINGLE thing in the 'update' that was a good change.

ElectricPavlov  Mar 21, 2017
#7
+152
+1

Thats so true honestly

xRainexSiderisx  Mar 21, 2017
#8
+7266
+4

Lol how about the hearts for points EP?

You gotta at least like them a little x)

hectictar  Mar 21, 2017
#9
+12735
+3

Nope.  Posted earlier that I thought the hearts were cheesy and the symbol should be something math-related like # or the pi symbol !   Just not feelin' the heart thingie ....

ElectricPavlov  Mar 21, 2017
#2
+7266
+4

All "solve for" means is get the variable by itself on one side of the equal sign.

$$a=\frac{v}{t}$$

Multiply both sides of the equation by t.

$$ta=v$$

Divide both sides of the equation by a.

$$t=\frac{v}{a}$$

Hey! time = velocity / acceleration

$$A = \pi r^2$$

Divide both sides of the equation by pi.

$$\frac{A}{\pi} = r^2$$

Take the + square root of both sides.

$$\sqrt{\frac{A}{\pi}} = r$$

radius = the square root of (area / pi)

The third one is exactly the same as the second one just with different letters.

hectictar  Mar 21, 2017
#5
+152
+2

Thank you so much!

xRainexSiderisx  Mar 21, 2017