+0  
 
+1
975
5
avatar+212 

An element is randomly chosen from among the first 15 rows of Pascal's Triangle. What is the probability that the value of the element chosen is ?

Note: The 1 at the top is often labelled the "zeroth" row of Pascal's Triangle, by convention. So to count a total of 15 rows, use rows 0 through 14.

 Aug 21, 2018
edited by ColdplayMX  Aug 21, 2018
 #1
avatar+212 
+1

An element is randomly chosen from among the first 15 rows. I might have left that out.

 Aug 21, 2018
 #2
avatar+129899 
+1

The  value of the element is    (what  ??? )

 

cool cool cool

 Aug 21, 2018
 #3
avatar+212 
0

a 1. sorry. :(

 Aug 21, 2018
 #4
avatar+129899 
+1

There  are  [ 15 * 16 ] / 2 =  15 * 8   = 120  elements in the first  15 rows of Pascal's Triangle

And there  are   14 * 2  + 1 = 29  "1s"  -   two "1s" on every row except for one on Row  "0"

 

So....the probability of choosing a "1"  is   29 / 120

 

 

cool cool cool

 Aug 21, 2018
 #5
avatar+212 
0

Thanks! 

 Aug 21, 2018

2 Online Users

avatar