+0  
 
+1
38
5
avatar+199 

An element is randomly chosen from among the first 15 rows of Pascal's Triangle. What is the probability that the value of the element chosen is ?

Note: The 1 at the top is often labelled the "zeroth" row of Pascal's Triangle, by convention. So to count a total of 15 rows, use rows 0 through 14.

ColdplayMX  Aug 21, 2018
edited by ColdplayMX  Aug 21, 2018
 #1
avatar+199 
+1

An element is randomly chosen from among the first 15 rows. I might have left that out.

ColdplayMX  Aug 21, 2018
 #2
avatar+88775 
+1

The  value of the element is    (what  ??? )

 

cool cool cool

CPhill  Aug 21, 2018
 #3
avatar+199 
0

a 1. sorry. :(

ColdplayMX  Aug 21, 2018
 #4
avatar+88775 
+1

There  are  [ 15 * 16 ] / 2 =  15 * 8   = 120  elements in the first  15 rows of Pascal's Triangle

And there  are   14 * 2  + 1 = 29  "1s"  -   two "1s" on every row except for one on Row  "0"

 

So....the probability of choosing a "1"  is   29 / 120

 

 

cool cool cool

CPhill  Aug 21, 2018
 #5
avatar+199 
0

Thanks! 

ColdplayMX  Aug 21, 2018

37 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.