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Given \(f(x)=x^2-6x+8\) and \(g(x)=x-2\) , solve \(f(x)=g(x)\)  using a table of values. Show your work.

THANK YOU! I really appreciate it!

Mar 21, 2019

#1
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\(f(x)=g(x) \)

\(f(x)=x^2-6x+8\\ g(x)=x-2\)

There will most likely be 2 answers becasue the power is 2

Fill in the grid

When you find 2 answer with f(x)=g(x) then those values of x are the only solutions.

 x -6 -5 -4 -2 -1 0 1 2 3 f(x) g(x) f(x)=g(x) ?

Mar 21, 2019
edited by Melody  Mar 21, 2019
#2
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Hi,

Im the creator of this question and wanted to solve it for anyone who needs help with a similar question because I didn't really understand Melody's answer. This was on of my practice questions on my study guide and found out later that my teacher said we didn't need to use a table of values so I solved it with my sister's help. :)

So it's a lot like algerbra except a lot more annoying in my opinion because i struggle with factoring. So you start by setting everything etting everything to zero.

\(x^2-6x+8=x-2 \)

Subtract x and ad 2 to both sides to set the equation equal to 0

\(x^2-7x+10=0\)

Factor

\((x-5)(x-2)=0\)

\(x-5=0\)

\(x-2=0\)

\(x = 5, 2\)

Really hope this helps anybody struggling with this. Can't 100% confirm this is right because this is my own work BUT this is how I got my answer for this question.

KennedyPape  Mar 22, 2019
#3
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The question SAID

using a table of values.

No one would ever use a table of values if the question did not state that it was a necessity.

You sister did not answer this question!

Melody  Mar 23, 2019
#4
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HOW  RUDE!

Mar 23, 2019
#5
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Melody,