This isn't as difficult as it seems...we just need to use some "creative" Algebra
4x^2 +9x - 6 = 0
In the form ax^2 + bc + c = 0
The sum of the roots, ( s + t ) = -b/ a = -9 / 4
The product of the roots, (st ) = c /a = -6/4 = -3/2
Note that we can write
s/t + t /s = [ s^2 + t^2 ] / st
And note that ( s + t)^2 = s^2 + 2st + t^2
So
(-/9/4)^2 = s^2 + 2(-3/2) + t^2
81/16 = -3 + [s^2 + t^2] ..... add 3 to both sides
81/16 + 3 = s^2 + t^2
81/16 + 48/16 = s^2 + t^2
129/16 = s^2 + t^2
So......
s/t + t/s = [ s^2 + t^2 ]/ st = [ 129/16] / [-3/2)] = [129/16] * [ -2/3] = -43 / 8
Here's the second one
2x^2 - 8x + 7 = 0
Let's write this in the form mx^2 + nx + q = 0 to avoid confusion with the roots
And we can write
1 / (2a) + 1 / (2b) = [a + b ] / [ 2ab ]
Using a similar idea as in the first one
The sum of the roots ( a + b) = -n/m = - (-8) / 2 = 8/2 = 4
The product of the roots ab = q/m = 7/2
So...
1/(2a) + 1/ (2b) =[ a + b ] / [2ab] = 4 / [ 2 (7/2) ] = 4 / 7