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Find the number of positive integers that are divisors of at least one of 10^10,15^7,18^11.

 Jul 1, 2020
 #1
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10^10 has 121 divisors, 15^7 has 64 divisors, 18^11 has 276 divisors.  All three numbers have a common divisors of 1, which is triple-counted, so the answer is 121 + 64 + 276 - 2 = 459.

 Jul 1, 2020
 #2
avatar+112 
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Sorry, but it sayd that thats wrong.

QuestionsBug  Jul 1, 2020

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