Find the number of positive integers that are divisors of at least one of 10^10,15^7,18^11.
10^10 has 121 divisors, 15^7 has 64 divisors, 18^11 has 276 divisors. All three numbers have a common divisors of 1, which is triple-counted, so the answer is 121 + 64 + 276 - 2 = 459.
Sorry, but it sayd that thats wrong.
+113 
