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Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit can be repeated in an integer?

 Jan 14, 2019
 #1
avatar+111435 
+1

For numbers with different digits we want to permute 2 choices out of 4 = 12

 

Plus the repeated digit numbers = 4

 

So

 

12 + 4   =   16   integers

 

 

cool cool cool

 Jan 14, 2019
 #2
avatar+145 
+2
16 integers can be made if you do the math. I can tutor you on google hangouts!
 Jan 14, 2019
 #3
avatar+25893 
0

4 choices for first digt  x  4 choices for second digit = 16 possibilities.

 Jan 14, 2019
 #4
avatar+111435 
0

I like your way better, EP......!!!!!

 

 

cool cool cool

CPhill  Jan 14, 2019

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