Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit can be repeated in an integer?

Guest Jan 14, 2019

#1**+1 **

For numbers with different digits we want to permute 2 choices out of 4 = 12

Plus the repeated digit numbers = 4

So

12 + 4 = 16 integers

CPhill Jan 14, 2019

#2**+2 **

16 integers can be made if you do the math. I can tutor you on google hangouts!

FreddieMercury Jan 14, 2019

#3**+1 **

4 choices for first digt x 4 choices for second digit = 16 possibilities.

ElectricPavlov Jan 14, 2019