+327 A spinner has five sectors of equal size. The sectors are labeled 1, 2, 3, 4, and 5. The spinner is spun twice. X is the number of times 3 is spun.
Drag each bar on the horizontal axis to the correct location to create a probability distribution for X.
So this is my answers but I know that they are not rght because they dont add up to 1.
Plus I have been looking at similar problems such as https://web2.0calc.com/questions/a-spinner-has-five-sectors-of-equal-size-the-sectors but dont understand how CPhill got the fraction for spin 2 and 3.
Please help me. I would really appreicate it. Thank you in advance.
+9479 Here's the list of possible outcomes from CPhill's answer:
1,1 2,1 3,1 4,1 5,1
1,2 2,2 3,2 4,2 5,2
1,3 2,3 3,3 4,3 5,3
1,4 2,4 3,4 4,4 5,4
1,5 2,5 3,5 4,5 5,5
num of outcomes where no 3 is spun = 16 so probability that num spins showing 3 is 0 = 16 / 25 = 0.64
num of outcomes where one 3 is spun = 8 so probability that num spins showing 3 is 1 = 8 / 25 = 0.32
num of outcomes where two 3's are spun = 1 so probability that num spins showing 3 is 2 = 1 / 25 = 0.04
Do you see where the 16, 8, and 1 come from? 
+327 THANK YOU SO MUCH!!!
I completely understand now! I made the mistake on the num of outcomes where two 3's are spun by thinking it was 9/25 (adding all the 3 outcomes together) than just 1/25.
THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
