Find the constant term in the expansion of (2z - 1/sqrtz)^9
it is not 5376
By the Binomial theorem, the constant term is C(9,2)*2^4 = 576.
Exapand (2z - 1/sqrt(z))^9
-5376 z^(9/2) - 1/z^(9/2) - 2016 z^(3/2) - 144/z^(3/2) - 2304 z^(15/2) + 512 z^9 + 4608 z^6 + 4032 z^3 + 18/z^3 + 672 The constant term is 672
Constant term is \(\displaystyle \binom{9}3 (2z)^3 \left(-\dfrac1{\sqrt z}\right)^6\). You can simplify this to get the constant term 672.
