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what is the perimeter of a square whose diagonal is 4√3? (Answer should be in simplified radical form)

Jan 22, 2020

#1
+9791
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what is the perimeter of a square whose diagonal is 4√3? (Answer should be in simplified radical form)

$$d=4\sqrt{3}$$

$$d=a\sqrt{2}$$

$$a\sqrt{2}=4\sqrt{3}\\ a=\frac{4\sqrt{3}}{\sqrt{2}}\\ p=4a=2\sqrt{2}\cdot \sqrt{3}$$

$$p=\sqrt{24}=4.899$$

$$The\ Perimeter\ is\ \sqrt{24}=4.899$$

!

Jan 23, 2020
#2
0

Given that a diagonal is [4 times sqrt(3)] which equals about 6.928 how can the perimeter be 4.899

You lost me at the line p = 4a = [2 times sqrt(2)] times sqrt(3)  (I think that's the length of a single side.)

.

Guest Jan 23, 2020
#3
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Is nobody going to correct the error in asinus' calculation?

Is the idea to ignore it until it's so far down in the pages it'll never be seen again?

Jan 26, 2020
#4
0

Asinus is notorious for fucking up solutions.

If we corrected all his fuckups, we’d never have time to fuckup our own answers!

Guest Jan 26, 2020
edited by Guest  Jan 26, 2020