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The real numbers x, y and z satisfy the equations x+2y+3z=950 and 3x+2y+z=1450 . What is the average of x, y and z ?

 Sep 7, 2020
 #1
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Very nice. Adding the two equations, we get 4x+4y+4z=2400 --> x+y+z=600. The average of x,y,z is (x+y+z)/3, so our answer is \(\frac{600}{3}=\boxed{200}\)

 Sep 7, 2020
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thank you!

xxJenny1213xx  Sep 7, 2020
 #3
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no problem

Guest Sep 7, 2020

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