The real numbers x, y and z satisfy the equations x+2y+3z=950 and 3x+2y+z=1450 . What is the average of x, y and z ?
Very nice. Adding the two equations, we get 4x+4y+4z=2400 --> x+y+z=600. The average of x,y,z is (x+y+z)/3, so our answer is \(\frac{600}{3}=\boxed{200}\)
thank you!
no problem
+617 
