web2.0calc
 
+0  
 

 Please help on this Geometry question.

0
364
6
avatar

A circle, with centre A and radius 3 cm, has two non-parallel tangents that touch the circle at points B and C. The tangets intersect at D(5,8).

i) Given that the area of the kite ABDC is 12 cm^2, calculate the length AD.
ii)Hence, or otherwise, find an equation for the locus of possible coordinates of A.

 

For part i) I found the length AD = 5 cm. 

Could anybody please help with part ii)? 
Is the answer: \(25=(x-5)^2+(y-8)^2\) ? As not sure what the question exactly wants.

 Oct 2, 2021

6+0 Answers

 #1
avatar
+1

https://doubleroot.in/lessons/coordinate-geometry-basics/locus-equation-1/

 

x2 + y2 = 9

 Oct 2, 2021
 #2
avatar
+1

I made an error...     x2 + y2 = 9  this is wrong!!!

 

x2 + y2 = 25

Guest Oct 2, 2021
 #3
avatar
+1

I'm wrong again...cheeky

 

Here's a good video about the subject::::   https://www.youtube.com/watch?v=kHQ50pJXUnU

Guest Oct 2, 2021
 #4
avatar
+1

Thanks... but why centered 0,0?

Guest Oct 2, 2021
 #5
avatar+1639 
+1

The equation for the locus.

 Oct 3, 2021
 #6
avatar
+1

Thank you jugoslav!! That's also what I got :))! And thanks to Guest, now I understand some of "Locus"

Guest Oct 3, 2021

2 Online Users

avatar

Top Users

avatar+128408 CPhill moderator
avatar+118608 Melody moderator
avatar+33615 Alan moderator
avatar+14905 asinus moderator
avatar+9519 MaxWong
avatar+3144 admin administrator
avatar+2440 GingerAle
avatar+1763 tomtom
avatar+1484 bader
avatar+1037 parmen
avatar+1030 blackpanther

Sticky Topics