+0  
 
0
45
3
avatar+20 

Please look at the picture through the link. The answer that I entered was c1=4/5, c2=3/5, d1=3/5, and d2=4/5. I came up with the conclusion when I drew a right triangle with a hypotenuse of 1 (unit circle) and a leg with 3/5, and another right triangle with a hypotenuse of 1 and a leg with 4/5. I solved for the missing sides (the cosines). My answer isn't correct, so may someone explain what I've done wrong? Thanks!

 

https://i.stack.imgur.com/Erfzk.png

 Jul 6, 2021
 #1
avatar+708 
0

Review your class transcript. This should give you a hint on how to start. Also look up the definitions and formulas relating to terminal points, and then with those you can find your answer.

 #3
avatar+120966 
+1

Only  one little error......

 

sin x  =  3/5     

cos  x =  4/5

 

a = (4/5 , 3/5)   this is OK

 

Rememnber  that   pi/2 < b <  pi....so....the  cos is negative  in ths quadrant

 

sin x  =  4/5

cos x=  -3/5

 

b= (-3/5, 4/5)

 

c1, c2 ,d1 , d2   =       4/5 , 3/5 , -3/5 , 4/5

 

Your answer seems correct.....maybe  the way you entered it  ???

 

 

cool cool cool

 Jul 6, 2021

5 Online Users