PLEASE HELP:) Solve the equation for the indicated variables.

1.) A=2x^2+4xh   , find x

OK, rearranging this, we have

2x^2 + 4hx = A         divide both sides by 2

x^2 + 2hx   = A/2      we need to complete the square, here....take 1/2 of the coefficient on x = (h) - square it, and add it to both sides....this gives

x^2 + 2hx + h^2  = A/2 + h^2      factor the left side

(x + h)^2 = A/2 + h^2                  take the square root of both sides......remember that we need to take the positive and negative roots on the right side.....so we have.......

x + h = ±√(A/2 + h^2)       subtract h from both sides

x = ±√(A/2 + h^2) - h     

( I have a feeling that x is supposed to be positive, since this equation seems to be relating to some type of area. )

2.) A=2(pi)r^2+2(pi)rh   , find r

This is similar to the last one.........divide both sides by 2pi..so we have

A/(2pi) = r^2 + 2hr       rearranging, we have

r^2 + 2hr = A/(2pi)       again, we need to complete the square ....so 1/2 of the coefficient on the x variable = h......square this and add to both sides...so we have...

r^2 + 2hr + h^2  = A/(2pi) + h^2        factor the right side

(r + h)^2  = A/(2pi) + h^2             take both roots

r + h = ±√( A/(2pi) + h^2)        subtract h from both sides

r = ±√( A/(2pi) + h^2) - h         ( here "r" is probably a positive value, so take the positive root)