+208 A four-digit natural number "abcd" is "balanced" if a + d = b + c. What is the probability that it is a "balanced" if a four-digit natural number is randomly selected?
+9589 I could not figure out a nice way to calculate the number of "balanced" numbers, but I wrote a Python program to count them.
The output of the program tells me that there are 615 "balanced" numbers. Hence, the required probability is \(\dfrac{615}{9000} = \dfrac{41}{600}\).
Would love to see a combinatorial approach to this problem.
+9589 I could not figure out a nice way to calculate the number of "balanced" numbers, but I wrote a Python program to count them.
The output of the program tells me that there are 615 "balanced" numbers. Hence, the required probability is \(\dfrac{615}{9000} = \dfrac{41}{600}\).
Would love to see a combinatorial approach to this problem.
