Please Help, Thank YOU if you try

The only thing you are "absolutely destroying" is your own education as you 'outsource' your homework questions .

Note that since the rectangles are congruent, we have DB = BF. That would imply $\angle BDF = \angle BFD$. Also, BE is perpendicular to EF, so $\angle BED = \angle BEF = 90^\circ$. Together with the common side BE we have the pair of congruent triangles $\triangle DEB \cong \triangle FEB$. Consequently we have the fact that E is the centre of the semi-circle. So we now have enough information to figure out that $\triangle DAE$ is equilateral. The rest is done through some angle chasing, which is not hard.