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A local hamburger shop sold a combined total of 614 hamburgers and cheeseburgers on Friday. There were 64 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Friday?

 

 Jan 11, 2019

Best Answer 

 #1
avatar+17332 
+3

Let x = hamburgers    then x+64 = cheeseburgers     ......   added together = 614

x +  x + 64 = 614

2x = 550

x = hamburgers = 275

 Jan 11, 2019
edited by ElectricPavlov  Jan 11, 2019
 #1
avatar+17332 
+3
Best Answer

Let x = hamburgers    then x+64 = cheeseburgers     ......   added together = 614

x +  x + 64 = 614

2x = 550

x = hamburgers = 275

ElectricPavlov Jan 11, 2019
edited by ElectricPavlov  Jan 11, 2019
 #4
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+1

Thank you so much!

Guest Jan 11, 2019
 #2
avatar+244 
+2

If we were trying to solve this problem, you have to make 2 equations. We have H and C to represent hamburgers and cheeseburgers, respectively. The problem states that the shop sold a combined total of 614 hamburger and cheeseburgers, the equation for this is:

 

H + C = 614

 

And the shop also states that there we 64 more cheeseburgers sold than hamburgers. This also means that it would take 64 more hamburgers to equal the number of cheeseburgers sold. So the equation for this is:

 

C = 64 + H

 

Now, we can substitute the second equation into the first equation. So what we get is:

 

2H + 64 = 614

 

Then solving,

 

2H = 550

 

H=275

 

This means that 275 hamburgers were sold on Friday.

 Jan 11, 2019
edited by CalculatorUser  Jan 11, 2019
 #3
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+1

Thank you so much!

Guest Jan 11, 2019

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