+0  
 
+1
547
1
avatar+226 

Let \(\omega \) be a complex number such that \(\omega^7 = 1\) and \(\omega \neq 1\). Let \(\alpha = \omega + \omega^2 + \omega^4\) and \(\beta = \omega^3 + \omega^5 + \omega^6\). Then \(\alpha\) and \(\beta\) are roots of the quadratic \(x^2 + px + q = 0\) for some integers p and q. Find the ordered pair (p,q).

 Sep 4, 2020
 #1
avatar
0

(p,q) = (8,-5).

 Sep 4, 2020

0 Online Users