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In a certain colony of bacteria, the number of bacteria doubles every day. The colony starts with 3 bacteria, and has 6 at the end of day 1, 12 at the end of day 2, and so on. What is the number of the first day which ends with the colony having more than 100 bacteria?

 Jul 26, 2021
 #1
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3 * 2n >100    n is the day number

2^n > 33.33

n = 6      day 6          day1=  6   ,  12 ,   24 ,   48 ,  96  ,   day 5 = 192

 Jul 26, 2021
 #2
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**** edit ****   typo.....answer does not change

 

n = 6      day 6          day1=  6   ,  12 ,   24 ,   48 ,  96  ,   day 6 = 192

ElectricPavlov  Jul 27, 2021

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