We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
523
5
avatar+4330 

A student accidentally added five to both the numerator and denominator of a fraction, changing the fraction's value to . If the original numerator was a 2, what was the original denominator?

 Sep 10, 2016
 #1
avatar+106046 
0

Your question is incomplete

 Sep 10, 2016
 #2
avatar+4330 
0

sorry this is good A student accidentally added five to both the numerator and denominator of a fraction, changing the fraction's value to 1/2 . If the original numerator was a 2, what was the original denominator?

 Sep 10, 2016
 #3
avatar+4330 
0

sorry this is good A student accidentally added five to both the numerator and denominator of a fraction, changing the fraction's value to 1/2 . If the original numerator was a 2, what was the original denominator?\

 

did u get the answer

 Sep 10, 2016
 #4
avatar
+5

If the original numerator was 2 and 5 was added to both sides, then that means:

2+5=7 the new numerator. But, after adding 5 to both sides it changed the value of the fraction to 1/2. This means that if numerator was 7, then the denominator would have to be 14, or 7/14 =1/2. Therefore, the original denominator would have to be: 14 - 5 =9. So, the original fraction was:

2/9. So that: [2 + 5] / [9 + 5] =7/14 =1/2.

 Sep 10, 2016
 #5
avatar+105411 
0

Let the original denominator  = A....so we know that

 

[ 2 + 5 ] / [ A + 5]  = 1/2     cross-multiply

 

2 [2 + 5]  = A + 5   simplify

 

2[7]  = A + 5

 

14  = A + 5     subtract 5 from both sides

 

9 = A

 

So......the original fraction  was 2/9

 

 

 

cool cool cool

 Sep 10, 2016

8 Online Users