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A, B and C are three points on a plane such that AB = BC = 1 and CA = \(\sqrt3\) Draw three circles whose diameters are \(\overline {AB}, \overline {BC}\) and \(\overline {CA}\) respectively. The area of the region included in all three circles (the grey region below) is \(\dfrac a b \pi +\dfrac {\sqrt c} d\) in simplest form, so a, b, c, d are positive integers, a and b are relatively prime, and c is not divisible by the square of a prime. Enter the values of a, b, c, d in order, separating by commas.

 

 

THANKS SO MUCH

 Feb 24, 2021
edited by Guest  Feb 24, 2021
 #1
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The area is 3/2*pi + sqrt(3)/2, so the answer is (3,2,3,2).

 Feb 24, 2021
 #2
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thanks,, but could you provide how you got the area to be that? 

Guest Feb 24, 2021

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