+2862 1. First add 5 to both sides
\(x^2-11x+19+5=-5+(5)\)
So you get \(x^2-11x+24=0\)
2. Then factor
Since 3 and 8 add up to 11 and they multiply to 24. The factored version of the left side of the equation is \((x-3)(x-8)=0\)
3. Solve
You multiply each side by (x-3) or (x-8) to get \(\boxed{x=3, x=8}\)
+2862 1. First add 5 to both sides
\(x^2-11x+19+5=-5+(5)\)
So you get \(x^2-11x+24=0\)
2. Then factor
Since 3 and 8 add up to 11 and they multiply to 24. The factored version of the left side of the equation is \((x-3)(x-8)=0\)
3. Solve
You multiply each side by (x-3) or (x-8) to get \(\boxed{x=3, x=8}\)
