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+2
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1. x^2 -11x+19= -5

Feb 12, 2019

#1
+2866
+4

1. First add 5 to both sides

\(x^2-11x+19+5=-5+(5)\)

So you get \(x^2-11x+24=0\)

2. Then factor

Since 3 and 8 add up to 11 and they multiply to 24. The factored version of the left side of the equation is \((x-3)(x-8)=0\)

3. Solve

You multiply each side by (x-3) or (x-8) to get \(\boxed{x=3, x=8}\)

Feb 12, 2019
edited by CalculatorUser  Feb 12, 2019

#1
+2866
+4

1. First add 5 to both sides

\(x^2-11x+19+5=-5+(5)\)

So you get \(x^2-11x+24=0\)

2. Then factor

Since 3 and 8 add up to 11 and they multiply to 24. The factored version of the left side of the equation is \((x-3)(x-8)=0\)

3. Solve

You multiply each side by (x-3) or (x-8) to get \(\boxed{x=3, x=8}\)

CalculatorUser Feb 12, 2019
edited by CalculatorUser  Feb 12, 2019
#2
+299
+1

Thank you!

Nerd123  Feb 12, 2019
#3
+120287
+1

Good job, CalculatorUser....!!!!

Feb 12, 2019