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Explain how would you find the measure of the largest angle measure of a triangle if given the measures of the three side lengths

 Mar 19, 2019
 #1
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\(\text{The largest angle is opposite the longest side}\\ \text{Use the law of cosines}\\ c^2 = a^2 + b^2 - 2 a b \cos(C)\\ \text{Where }c \text{ is the length of the longest side, and }\\ a,b \text{ are the lengths of the other two sides}\)

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 Mar 19, 2019
 #2
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So, the measure of the largest angle measure of a triangle is:

 

Angle C = Arc Cosine [(a^2+b^2-c^2) / 2ab]
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Guest Mar 20, 2019

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