What is the area of △PQR.
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Let QR be the base of the triangle.
Let's draw a height from QR to P .
Now we have a right triangle.
sin( angle ) = opposite / hypotenuse
sin 20° = h / 9
Multiply both sides of the equation by 9 .
9 sin 20° = h
h = 9 sin 20°
Now we know the base and the height, so we can find the area.
area = (1/2)(base)(height)
area = (1/2)(14)(9 sin 20°) square cm
area = 63 sin 20° square cm
area ≈ 21.5 square cm