Please Help w/ Geometry Question!!! {3/27/18}

Let  QR  be the base of the triangle.

Let's draw a height from  QR  to  P .

Now we have a right triangle.

sin( angle )  =  opposite / hypotenuse

sin 20°  =  h / 9

                            Multiply both sides of the equation by  9 .

9 sin 20°  =  h

h  =  9 sin 20°

Now we know the base and the height, so we can find the area.

area  =  (1/2)(base)(height)

area  =  (1/2)(14)(9 sin 20°)   square cm

area  =  63 sin 20°   square cm

area  ≈  21.5   square cm