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A cube-shaped aquarium has edges that are 3 ft long. The aquarium is filled with water that has a density of 62 Ib/ft^3 .

(a) Should the aquarium be placed on a table that can support a maximum weight of 200 lb? Explain why or why not.

(b) Would the density of the water change if the aquarium was only half full? Explain.

Thank You For Helping Me!!!

KennedyPape May 10, 2018

#1**+1 **

**(a)**

volume of aquarium = (3 ft)^{3} = 27 cubic feet

The water has a density of 62 pounds per cubic foot.

weight of 1 cubic foot of water = 62 pounds

weight of 27(1) cubic feet of water = 27(62) pounds

weight of 27 cubic feet of water = 1674 pounds

The water weight of the full aquarium is 1674 pounds, and the table only supports 200 pounds, so the table cannot hold the aquarium.

**(b)**

No, the density of the water would not change.

hectictar May 10, 2018