A cube-shaped aquarium has edges that are 3 ft long. The aquarium is filled with water that has a density of 62 Ib/ft^3 .

(a) Should the aquarium be placed on a table that can support a maximum weight of 200 lb? Explain why or why not.

(b) Would the density of the water change if the aquarium was only half full? Explain.

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KennedyPape May 10, 2018

#1**+1 **

**(a)**

volume of aquarium = (3 ft)^{3} = 27 cubic feet

The water has a density of 62 pounds per cubic foot.

weight of 1 cubic foot of water = 62 pounds

weight of 27(1) cubic feet of water = 27(62) pounds

weight of 27 cubic feet of water = 1674 pounds

The water weight of the full aquarium is 1674 pounds, and the table only supports 200 pounds, so the table cannot hold the aquarium.

**(b)**

No, the density of the water would not change.

hectictar May 10, 2018