Let a and b be positive lengths, and consider the following triangles:
Then what are
\(\angle A, \angle D, \angle G \) in radians, in that order?
I need the steps so I can see how you did it. I don't just want answers.
I am going to use the law of cosines since we have the sides.
sqrt(a^2 + absqrt(3) + b^2)^2 = b^2 + a^2 - 2abcos(A)
a^2 + absqrt(3) + b^2) = b^2 + a^2 - 2abcos(A)
absqrt(3) = - 2abcos(A)
-sqrt(3)/2 = cos(A)
A = arccos(-sqrt(3)/2) = 2.61799388 radians