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Let a, b, c, d are all prime numbers, and they meet the following guidelines: a>3b>6c>12d and a^2-b^2+c^2-d^2=1749 Please determine all the possible values of a^2+b^2+c^2+d^2.

 

I got that d=2 but that's about it. 

 Jan 29, 2019
 #1
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+1

One scenario could be as follows:

 

43^2 - 11^2 + 5^2 - 2^2 = 1749

Here is another way:

59^2 - 43^2 + 11^2 - 2^2 = 1749 {This does not meet the condition: a>3b>6c>12d}

Note: Simply by trial and error.

 Jan 29, 2019
edited by Guest  Jan 29, 2019
edited by Guest  Jan 29, 2019
 #2
avatar+283 
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Thank you but is it possible to show me how you have arrived at that answer? 

yasbib555  Jan 29, 2019
 #3
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Let a, b, c, d are all prime numbers, and they meet the following guidelines: a>3b>6c>12d and a^2-b^2+c^2-d^2=1749

Please determine all the possible values of a^2+b^2+c^2+d^2.

I got that d=2 but that's about it. 

 

see: https://answers.yahoo.com/question/index?qid=20190129142548AAZETxJ&guccounter=1

 

laugh

 Jan 30, 2019

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