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https://web2.0calc.com/questions/please-help-me_49

Guest Oct 30, 2018
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Expanding the terms, 

 

\((x^2+2xh+h^2)+(y^2+2yh+y^2)=(a^2+2ab+b^2) \)

 

Using Pythagorean Theorem,

 

\(x^2+h^2=a^2\\ y^2+h^2=b^2\)

 

We could subsitute the values in, and rewrite the equation

 

\(a^2+2xh+b^2+2yh=a^2+2ab+b^2\\ 2xh+2yh=2ab\\ h(x+y)=ab \)

 

\([ABC]=\frac12 AB\cdot CH = \frac12 BC \cdot AC\\ \frac12 (x+y)h=\frac12 ab\\ h(x+y)=ab\)

 

I hope this helped,

 

Gavin

GYanggg  Oct 30, 2018

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