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The equation of the perpendicular bisector of the line segment joining the points $(-3,8)$ and $(-5,4)$ is $y = mx + b$. Find $m+b$.

 Feb 27, 2020

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 #1
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The slope of the line segment is (8 - 4)/(-5 - (-3)) = -2, so the slope of the perpendicular bisector is 1/2.

 

The midpoint is (-4,6), so by point-slope form, the equation fo the line is y - 6 = 1/2(x + 4).

 

Then y = 1/2*x + 8, so m + b = 1/2 + 8 = 17/2.

 Feb 27, 2020
 #1
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+1
Best Answer

The slope of the line segment is (8 - 4)/(-5 - (-3)) = -2, so the slope of the perpendicular bisector is 1/2.

 

The midpoint is (-4,6), so by point-slope form, the equation fo the line is y - 6 = 1/2(x + 4).

 

Then y = 1/2*x + 8, so m + b = 1/2 + 8 = 17/2.

Guest Feb 27, 2020

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