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Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

 Mar 16, 2019
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Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

 

If f(0) is 47, then the constant term =  47

 

And if  f(1) = 32.....then the sum of all the coefficients and the constant  must be = 32

 

So....the sum of the coefficients, S,  must be

 

S + 47 =  32        subtract  47 from both sides

 

S =  -15     =    sum of the coefficients

 

 

cool cool cool

 Mar 16, 2019

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