+150 Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?
+129850 Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?
If f(0) is 47, then the constant term = 47
And if f(1) = 32.....then the sum of all the coefficients and the constant must be = 32
So....the sum of the coefficients, S, must be
S + 47 = 32 subtract 47 from both sides
S = -15 = sum of the coefficients
