From a standard deck of 52 cards, the four Aces, four 2's, and four 3's are drawn, forming a smaller deck of 12 cards. All 12 cards are dealt at random to four players, so that each player gets three cards. What is the probability that each player's hand consists of an Ace, a 2, and a 3?
Don't answer I just need guidance cus I did 1/3*4/11*4/10 because each was a different chance of getting one of the cards for each person. However, this is incorrect so can someone help me thank you!!!
your thinking is in the right direction. Are you considering the cases where the Ace isn't the first one drawn?(becaues I'm assuming the order does matter in which you draw them). As such, I would try multipliying by the number of ways that you can draw the hand given(in other words, an Ace, a 2, and a 3)