Find all solutions to the inequality \(\frac{(2x-7)(x-3)}{x} \ge 0. \)
Please enter in interval notation.
(2x - 7) ( x - 3)
____________ ≥ 0
x
Note that
2x - 7 ≥ 0
2x ≥ 7
x ≥ 7/2
So all values of x ≥ 7/2 will make the inequality true
And note that when x is on the interval (0 , 3 ] it will also be true
And when x < 0 it is never true
So......the intervals that make this true are
(0, 3 ] U [ 7/2, inf)
Here's the graph to show this :
https://www.desmos.com/calculator/zrszwkjmby