Please Help!

Question

Please Help!

0

834

1

I don't understand it:

If the odds for pulling a prize out of the box are 3:4, what is the probability of not pulling the prize out of the box? Express your answer as a common fraction.

Thanks in advance!

Guest Mar 3, 2019

Best Answer

1⁺⁰ Answers

#1

+6252

+1

Best Answer

$\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}$

$\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7$

$P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7$

Rom Mar 3, 2019

1 Online Users

Rom · Answer 1 · 2019-03-03T11:20:13

$\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}$

$\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7$

$P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7$

.

Please Help!

0 users composing answers..

Best Answer

1⁺⁰ Answers

1 Online Users

Top Users

Sticky Topics

Please Help!

0 users composing answers..

Best Answer

1+0 Answers

1 Online Users

Top Users

Sticky Topics

1⁺⁰ Answers