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I don't understand it:

If the odds for pulling a prize out of the box are 3:4, what is the probability of not pulling the prize out of the box? Express your answer as a common fraction.

Mar 3, 2019

#1
+5226
+1

$$\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}$$

$$\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7$$

$$P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7$$

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Mar 3, 2019

#1
+5226
+1

$$\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}$$

$$\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7$$

$$P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7$$

Rom Mar 3, 2019