We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
140
1
avatar

I don't understand it:

 

If the odds for pulling a prize out of the box are 3:4, what is the probability of not pulling the prize out of the box? Express your answer as a common fraction.

 

Thanks in advance!

 Mar 3, 2019

Best Answer 

 #1
avatar+6045 
+1

\(\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}\)

 

\(\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7\)

 

\(P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7\)

.
 Mar 3, 2019
 #1
avatar+6045 
+1
Best Answer

\(\text{odds of doing X} = \dfrac{P[\text{doing X}]}{P[\text{Not doing X}]}=\dfrac{P[\text{doing X}]}{1-P[\text{doing X}]}\)

 

\(\text{odds of pulling prize }=\dfrac{3}{4} \Rightarrow P[\text{pulling prize}] = \dfrac{3}{3+4}= \dfrac 3 7\)

 

\(P[\text{not pulling prize}]=1-P[\text{pulling prize}] = \\ 1 - \dfrac 3 7 = \dfrac 4 7\)

Rom Mar 3, 2019

10 Online Users