In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse
+1490 In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse
(x+5)2+(x+10)2=(x+15)2
Step 1: Simplify both sides of the equation.
2x2+30x+125=x2+30x+225
Step 2: Subtract x2 from both sides.
2x2+30x+125−x2=x2+30x+225−x2
x2+30x+125=30x+225
Step 3: Subtract 30x from both sides.
x2+30x+125−30x=30x+225−30x
x2+125=225
Step 4: Subtract 125 from both sides.
x2+125−125=225−125
x2=100
x = 10
sqrt [(10+5)2 + (10+10)2] = 25 cm 
