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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse

Mar 11, 2020

#1
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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse

(x+5)2+(x+10)2=(x+15)2

Step 1: Simplify both sides of the equation.

2x2+30x+125=x2+30x+225

Step 2: Subtract x2 from both sides.

2x2+30x+125−x2=x2+30x+225−x2

x2+30x+125=30x+225

Step 3: Subtract 30x from both sides.

x2+30x+125−30x=30x+225−30x

x2+125=225

Step 4: Subtract 125 from both sides.

x2+125−125=225−125

x2=100

x = 10

sqrt [(10+5)2 + (10+10)2] = 25 cm Mar 11, 2020
edited by Dragan  Mar 11, 2020
edited by Dragan  Mar 11, 2020
#2
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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse  Mar 11, 2020
edited by Omi67  Mar 11, 2020
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As someone put it:

" An error does not become a mistake until you refuse to correct it. " Dragan  Mar 11, 2020
edited by Dragan  Mar 11, 2020
edited by Dragan  Mar 12, 2020