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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse

 Mar 11, 2020
 #1
avatar+1485 
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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse

 

(x+5)2+(x+10)2=(x+15)2

Step 1: Simplify both sides of the equation.

2x2+30x+125=x2+30x+225

Step 2: Subtract x2 from both sides.

2x2+30x+125−x2=x2+30x+225−x2

x2+30x+125=30x+225

Step 3: Subtract 30x from both sides.

x2+30x+125−30x=30x+225−30x

x2+125=225

Step 4: Subtract 125 from both sides.

x2+125−125=225−125

x2=100

x = 10

 

sqrt [(10+5)2 + (10+10)2] = 25 cm  indecision

  

 Mar 11, 2020
edited by Dragan  Mar 11, 2020
edited by Dragan  Mar 11, 2020
 #2
avatar+12525 
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In a right triangle, one of the legs is 5 cm smaller than the hypotenuse, and the other leg is 10 cm smaller than the hypotenuse. Find the length of the hypotenuse

laugh

 Mar 11, 2020
edited by Omi67  Mar 11, 2020
 #3
avatar+1485 
0

As someone put it:

" An error does not become a mistake until you refuse to correct it. "  smiley

Dragan  Mar 11, 2020
edited by Dragan  Mar 11, 2020
edited by Dragan  Mar 12, 2020

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