+128 △ABC is a right triangle with right angle at ∠B .
AB=34 cm
AC=55 cm
What is the measure of ∠C , to the nearest degree?
+193 AB= 34, so c = 34
AC= 55, so a = 55
angle B = 90 degrees
a^2 + b^2 = c^2
55^2 + b^2 = 34 ^2
3025 + b^2 = 1156
-3025 -3025
b^2 = -1869
square root booth sides, and round to nearest tenth.
b = + or - 43.2
since this is length it has to be positive
b = 43.2
now
sin C/ c = sin B/b
sin C/34 = sin 90/43.2
43.2 sin C = 34 sin 90
sin C = (34 sin 90)/ 43.2
(sin C) sin^-1= (34 sin 90/ 43.2) sin^-1
C = your answer
