+0  
 
0
1618
3
avatar+128 

△ABC is a right triangle with right angle at ∠B .

AB=34 cm 
AC=55 cm

 

What is the measure of ∠C , to the nearest degree?

Acceptfully  Apr 20, 2017
edited by Acceptfully  Apr 20, 2017
 #2
avatar+193 
0

AB= 34, so c = 34

AC= 55, so a = 55

angle B = 90 degrees

a^2 + b^2 = c^2

55^2 + b^2 = 34 ^2

3025 + b^2 = 1156

-3025             -3025

b^2 =  -1869

square root booth sides, and round to nearest tenth.

b = + or - 43.2

since this is length it has to be positive

b = 43.2

now

sin C/ c = sin B/b

sin C/34 = sin 90/43.2

43.2 sin C = 34 sin 90

sin C = (34 sin 90)/ 43.2

(sin C) sin^-1= (34 sin 90/ 43.2) sin^-1

C = your answer

Snappingtunic99  Apr 20, 2017
 #3
avatar+128 
0

I'm not sure how to do (sin C) sin^-1= (34 sin 90/ 43.2) sin^-1

Acceptfully  Apr 20, 2017

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